Singly Reinforced Section design
Beam design can be done for different codes depending on specific requirements. Before designing a beam, first, we need to find the bending moments and shear forces of the beam section through an analysis.
BS 8110 part 01 is one of the most commonly used standards, and the method expressed in the code can be understood very easily compared guides given for the design of other elements.
Design example
Design Data
Bending Moment = 250 kNm
Shear Force = 200 kN
Beam width = 225 mm
Beam height = 600 mm
Grade of the concrete = 25 N/mm2
Strength of the steel = 460 N/mm2
Cover to R/F = 30 mm
Shear links diameter = 10 mm
No redistribution of the moment is assumed.
Calculations
effective depth = 600-30-10-20/2
= 550 mm
K = M/bd2fcu
= 250×106/(225×5502x25)
= 0.147
K < K’ = 0.156
Hence, the section is singly reinforced.
Z = d[0.5+{0.25-K/0.9}1/2]
= 550[0.5+{0.25-0.147/0.9}1/2]
= 436.995 mm
As = M / (0.95fyZ)
= 250×106 / (0.95x460x436.995)
= 1309 mm2
Provide three 25 mm bars.
The properly designed beam could fail due to many reasons. Article 6 causes of beam failures could be read for more information.